Question

Q10. A particle starts to move in a straight line from a point with velocity 10 m/s and
acceleration -2.0 m/s Find position and velocity of the particle at(i) t=5s,(ü) t=10s. [Ans(i)o(u)10
m/s]



pls answer correct I will follow u but correct​

Answer 1

Answer:

x=at^2 ÷2 + ut

= -2×5×5/2 +10×5

= -25 +50

= 25

v =u + at

= 10 -2×5

= 0

at t=10

X = -2×10×10/2 +10×10

= -100 +100

=0

v = 10 -2×10

= -10