Q10) AB is parallel to CD < BAC = (3x + 15)° < ACD = (2x +45)°find value of x
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Answer:3x+15=2x+45
3x-2x=45-15
x=30°
BAC=3x+15
3(30)+15
105°
ACD=2x+45
2(30)+45
105
Step-by-step explanation:
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