Question

q10 and q 11 ans pls quick

Answer 1

No cheating

I just got a free point

Answer 2

Answer:

i will do only half

the remaining you have to find by your own

Q10) let the cost of first article be x Rs.

Gain = 25%

total money the man got on selling the articles = 375 Rs.

money of first article he got = cost + profit

$money\ of\ first\ article\ he\ got= x + (x \times \frac{25}{100} )\\\\money\ of\ first\ article\ he\ got= x + (x \times \frac{1}{4} )\\\\money\ of\ first\ article\ he\ got= x + \frac{x}{4} \\\\money\ of\ first\ article\ he\ got= \frac{4x}{4} + \frac{x}{4}\\\\money\ of\ first\ article\ he\ got= \frac{5x}{4}Rs.$

total money the man got on selling the articles = 375 Rs.

∴money of first article he got + money of second article he got= 375

$\frac{5x}{4} + money\ of\ second\ article\ he\ got=375\\\\money\ of\ second\ article\ he\ got = 375-\frac{5x}{4}\\\\money\ of\ second\ article\ he\ got = \frac{375(4)}{4}-\frac{5x}{4}\\\\money\ of\ second\ article\ he\ got = \frac{1500}{4}-\frac{5x}{4}\\\\money\ of\ second\ article\ he\ got = \frac{1500-5x}{4}$

Now we will find the cost of second article,

money of second article he got = cost of second article - loss

$\frac{1500-5x}{4} = cost\ of\ second\ article - \frac{25}{100} \\\\cost\ of\ second\ article =\frac{1500-5x}{4} + \frac{1}{4} \\\\cost\ of\ second\ article =\frac{1500-5x+1}{4}\\\\cost\ of\ second\ article =\frac{1501-5x}{4}$

Cost he paid for articles = cost of first article + cost of second article

$Cost\ he\ paid\ for\ articles = x + \frac{1501-5x}{4}\\\\Cost\ he\ paid\ for\ articles = \frac{4x}{4} + \frac{1501-5x}{4}\\\\Cost\ he\ paid\ for\ articles = \frac{1501-5x+4x}{4}\\\\Cost\ he\ paid\ for\ articles = \frac{1501-x}{4}$

find by your own