Question

Q10) Find the Pythagorean triplet whose smallest number is 12
a) (34,36,12)
b) (36,34,12
c) (12,35,37)
d) (12,5,6)

Answer 1

Answer:

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Step-by-step explanation:

c) (12,35,37)

Answer 2

Answer:

c) 12,35,37

Step-by-step explanation:

For every natural number m > 1, (2m,m2-1,m2+1) is a Pythagoras triplet.

Putting 2m = 12, we get m = 6.

=> m2-1 = (6)2 - 1

= 36 - 1

= 35

=> M2 + 1 = (6)2 + 1

= 36 + 1

= 37

Hope this solution will help you.