Question

Q10) Find the semi perimeter of a triangle having sides 45cm ,49cm and 96cm.​

Answer 1

Given :-

• A triangle having sides 45 cm, 49 cm and 96 cm.

To Find :-

• The Semi Perimeter of traingle = ?

Answer :-

• The Semi Perimeter of traingle = 95 cm

Explaination :-

As we know that, Semi Perimeter of ∆ is given by formula :

• Semi Perimeter = a + b + c ÷ 2

Where, the sides of ∆ is :

◪ a = 45 cm

◪ b = 49 cm

◪ c = 96 cm

Now, subsitute the value of a, b, c in above given formula :

→ Semi Perimeter = 45 + 49 + 96 ÷ 2

→ Semi Perimeter = 190 ÷ 2

→ Semi Perimeter = 95 cm

Hence,Semi Perimeter of traingle is 95 cm.

Extra Shots :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

Answer 2

Answer:

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: Question :- \: \star}}}}}$

Find the semi perimeter of a triangle having sides 45 cm ,49 cm and 96 cm .

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$\red{\bigstar}$ Semi perimeter [P]

$\huge\leadsto{\sf\purple{95 \: cm}}$

$\Large{\underline{\underline{\bf{GiVen:-}}}}$

Triangle having sides 45cm ,49cm and 96cm.

$\Large{\underline{\underline{\bf{Find:-}}}}$

❥ What's the semi perimeter of a triangle ?

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

Here we go !

As we know ,

Perimeter of Triangle = Sum of all the sides

Perimeter of Triangle = ( a + b + c )

Now,

What's the semi perimeter is ?

Its just the half of perimeter

So ,

Semi perimeter of a triangle = a + b + c ÷ 2

As according to given ,

Sides of triangle are 45cm ,49cm and 96cm respectively .

Applying above formula

↠ Semi Perimeter = ( 45 + 49 + 96 ÷ 2 )

= 190 ÷ 2

= 95 cm

$\underline{\boxed{\textsf{ s = {\textbf{95}}}}} \qquad\qquad \bigg\lgroup\bold{Semi \ perimeter \ of \ triangle} \bigg\rgroup$

Additional Information :-

❥ Perimeter of Rectangle = 2( L + B )

❥ Perimeter of square = 4 × Side

❥ Perimeter of triangle = AB + BC + CA

❥ Area of Rectangle = L × B

❥ Area of Square = ( side ) ²

❥ Area of Rhombus = Product of Diagonal/2.

❥ Area of Parallelogram = Base × Height.

❥ Area of triangle = 1/2 × base × height .

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