Q10 Find the value of p, so that (3P+
7), (2p+5), (2p + 7) are in A.P
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Answered by
14
for becoming an A.P.2p+7-2p-5=2p+5-3p-7
p=4
Answered by
0
a + c = 2b
(3P+7) + (2p + 7) = 2(2p+5)
5p + 14 = 4p + 10
5p - 4p = 10 - 14
p = -4
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