Question

Q10) Fnd the mean and median of : 3.2.6.3.3.1.1.2 ?​

Answer 1

Answer:  

The median of the following numbers is 2.5

Step-by-step explanation:

Median is the middle number  

Arrange in ascending order or descending order

1, 1, 2, 2, 3, 3, 3, 6

If the number is even then add the 2 middle number then divide by 2

Here, 2 & 3

(2 + 3) ÷ 2

5 ÷ 2

2.5

The median of the following numbers is 2.5

Answer 2

Answer:

Mean = 2.625

Median = 2.5

Formula used

$\star \: \: {\small{\boxed{\tt{\blue{Mean = \frac{Sum \: of \: all \: observations}{No. \: of \: observations}}}}}}$

$\star \: \: {\small{\boxed{\tt{\blue{Median = Mean \: of \: ( \frac{n}{2})^{th}+(\frac{n}{2}+1)^{th} \: term}}}}}$

Step-by-step explanation:

${\small{\sf{Mean = \frac{3+2+6+3+3+1+1+2}{8}}}} \\ {\small{\sf{= \frac{21}{8} }}} \\ {\small{\sf{= 2.625}}}$

Before finding median we have to write the given set of no. in ascending or descending order

1, 1, 2 ,2, 3, 3, 3, 6

Now ,

Find the median using above formula

where, n = no. of observations

${\small{\sf{Median = mean\: of\: ( \frac{8}{2})^{th}+(\frac{8}{2}+1)^{th} \: term}}} \\ {\small{\sf{= mean \: of \: ( {4})^{th} + ( {4 + 1})^{th} \: term}}} \\ {\small{\sf{= mean \: of \: ({4})^{th} + {(5)}^{th} \: term}}}$

Now, put the values of 4th and 5th term

${\small{\sf{Median = mean \: of \: 2 \: and \: 3}}} \\{\small{\sf{ = \frac{2 + 3}{2} }}} \\ {\small{\sf{= \frac{5}{2} }}} \\ {\small{\sf{= 2.5 }}}$

Additional Info

Note -

• Median of even no. of observations = mean of (n/2)th term and (n/2 +1)th term
• Median of odd no. of observations = (n+1/2)th term