Question

Q10. Given that in H-atom, the transition energy for n = 1 to n = 2 is 10.2 eV,
the energy for the same transition in Be3+ is​

Answer 1

Answer:

The energy required to excite an electron from n = 1 to n = 2 is 163.2eV.

Explanation:

The formula used to calculate the energy of excitation is given as follows:

where,

Z = atomic number = 4 (for beryllium)

n = Energy level

The transition of ionization energy is from  

Putting values in above equation, we get:

Hence, the energy required to excite an electron from n = 1 to n = 2 is 163.2eV.

Explanation:

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Answer 2

Answer:

For hydrogen like species like Be 3+ , E n =

Z 2 E n for hydrogen atom.

E n =4 2 ×10.2=16×10.2=163.2eV

Explanation:

Answer by @Missmiracle12 ❤️