Question

Q10 If the product of the zeroes of the quadratic polynomial

p(x)=(k-2)x2-4x+k is 3 then the value of k is

(a) 2 (b) -2 (c)3 (d) -3
​

Answer 1

Answer:

Let α & β be the zeroes of the polynomial...

p(x) = (k-2)x²-4x+k

a = (k-2) , b = -4 , c = k

Given, αβ = 3

We know that,

αβ = c/a

3 = k/ (k-2) [ αβ = 3 ]

(k-2) * 3 = k

3k-6 = k

3k-k = 6

2k = 6

k = 3

option c

Answer 2

Answer:

k=3

Step-by-step explanation:

we know

product of zeroes in quadratic polynomial

ax²+bx+c is c/a

so a/q

3=k/k-2

k=3