Question

Q10. Number of electron present in a
negative charge of 8 C is.​

Answer 1

Answer:

Magnitude of charge  Q=8 C

Magnitude of one electronic charge  e=1.6×10−19 C

Let the number of electron present be N.

Thus, number of electrons   N=eQ

⟹ N=1.6×10−198=5×1019