Question

Q10 please help
It’s of Quadratic Equation chapter
I want 3ans of this equation PLZZ ans help me

Answer 1

Answer:

x = -1, 1, (3 + √13)/2, (3 - √13)/2

Step-by-step explanation:

Given Equation is (x² + 1/x²) - 3(x - 1/x) - 2 = 0

⇒ x² + 1/x² - 3x + 3/x - 2 = 0

⇒ x⁴ + 1 - 3x³ + 3x - 2x² = 0

⇒ (x + 1)(x - 1)(x² - 3x - 1) = 0

(i)

x + 1 = 0

x = -1

(ii)

x - 1 = 0

x = 1

(iii)

x² - 3x - 1 = 0.

On comparing with ax² + bx + c = 0.

a = 1, b = -3 ,c = -1

D = b² - 4ac

   = (-3)² - 4(1)(-1)

   = 9 + 4

   = √13.

(a)

x = -b+√D/2a

  = -(-3) + √13/2

  = (3 + √13)/2

(b)

x = -b - √D/2a

  = -(-3) - √13/2

  = (3 - √13)/2

Therefore, the values of x = -1, 1,  (3 + √13)/2,  (3 - √13)/2.

Hope it helps!

Answer 2

Step-by-step explanation:

10.

(x^2 + 1/x^2) - 3(x-1/x) - 2 = 0

(x^2 + 1/x^2) - 4(x - 1/x) + (x - 1/x) - 2 = 0

x = 1,-1.