Q10 please solve step by step
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Step-by-step explanation:
sum of three consecutive terms = 48
product of first and third term = 252
let the consecutive terms be
a - d, a, a + d
sum of these is 48
a - d + a + a + d = 48
3a = 48
a = 48/3
a = 16
product of first and third term = 252
(a - d) × (a + d) = 252
a² - d² = 252
16² - d² = 252
256 - d² = 252
d² = 256 - 252
d² = 4
d = √4
d = 2
therefore the common difference = 2
the AP is
a - d = 16 - 2 = 14
a = 16
a + d = 16 + 2 = 18
14, 16, 18
Hope you get your answer
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