Question

Q10. Point A is chosen on y – axis where ΔABC is an equilateral triangle, the base BC = 6unit, find the coordinates

of: (I) Mid - point of BC (II) find length OA (O is mid- point of BC (III) find coordinate of vertex A.​

Answer 1

Answer:

O is the mid-point of the base BC.

Therefore, coordinates of point B are (0,3).

So, BC = 6 units

Let the coordinates of point A be (x,0).

Using distance formula,

AB=

(0−x)

2

+(3−0)

2

=

x

2

+9

BC=

(0−0)

2

+(−3−3)

2

=

36

Also, AB = BC

x

2

+9

=

36

x

2

+9=36

x

2

=27

x=±3

3

Coordinates of A = (3

3

,0).

solution

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