Question

| Q10.) The age of a mother is twice that of
the elder daughter. Ten years hence the age
of the mother will be three times that of
the younger daughter. If the difference of
ages of the two daughter is 15 years, what
is the age of the mother ?​

Answer 1

Let x represent the mother's age.  

Then the elder daughter would be x/2  

In ten years, the younger daughter's age can be represented by (x+10)/3; subtracting ten from this would give her current age: ((x+10)/3)-10  

Since the daughters are 15 years apart, subtract the younger daughter's age from the elder's age and set it equal to 15.  

x%2F2-%28%28x%2B10%29%2F3-10%29=15  

 

Now multiply by the LCD which is 6 (2*3)  

6%28x%2F2-%28%28x%2B10%29%2F3-10%29%29=15%2A6  

3x-2%28x%2B10%29-60=90  

3x-2x-20%2B60=90  

x%2B40=90  

x=50  

X represented the mother's age, so the mother is 50 years old.

Answer 2

Step-by-step explanation:

the answer will be 50 years let m is equal to 280 where is the age of mother and he is the age of elder daughter now m is equal to 2 according to the question let why is the age of younger doubt are there in + 10 is equal to 3 into Y + 10 Shoaib + 10 is equal to 3 + 3 Y + 30 Shoaib minus 3 Y is equal to 20 now we have two equation 2 x minus 3 is equal to 20 and 2 - 2 Y is equal to 30 on solving this we get Y is equal to 10 and putting this value in the equation a minus 3 Y is equal to 20 20 we get y m is equal to 50