Question

Q10. The length of a rectangle is 10 m more than its breadth. If the perimeter of
rectangle is 80 m, find the dimensions of the rectangle?​

Answer 1

Let the breadth be x

Length=10+x

Perimeter=2(l+b)

80=2(10+x+x)

$\frac{80}{2}=10+2x\\40=2x+10\\30=2x\\ \frac{30}{2}=x=15$

breadth=15

length=25

Answer 2

Answer:

Step-by-step explanation: let the breadth=W

length=10 W, Perimeter=80 m

since the perimeter of a rectangle= 2(L+B)

therefore, P=2(10 W+W)

80=2(11 W)

80=22 W

80/22=W

3.63 m=W

L=10 W

L=10*3.63= 36.3 m

L=36.3 m

W=3.63 m