Math, asked by yadav3098, 4 months ago

Q10 The length of rectangle is 5.8 cm and breadth is 3.5 cm. Then what is the area and perimeter of rectangle?

Answers

Answered by ItzRadhika
34

\bf\underline{\underline{\green{SOLUTION:-}}}

Question

  • The length of rectangle is 5.8 cm and breadth is 3.5 cm. Then what is the area and perimeter of rectangle?

Answer

  • Perimeter = 18.6cm
  • Area = 20.3 cm²

Given

  • Length of rectangle = 5.8cm
  • Breadth = 3.5

To Calculate ji8

  • Area & Perimeter __?

Step by Step Explanation

Length of rectangle = 5.8cm ( Given )

Breadth of rectangle = 3.5 cm ( Given )

Area of rectangle = Length × Breadth

➺ 5.8×3.5

➺ 20.3

Area = 20.3 cm²

Perimeter = Sum of all sides

➺ 2(5.8+3.5)

➺ 2×9.3

➺ 18.6

Perimeter = 18.6cm

\bf\underline{\underline{\green{SOLUTION:-}}}

  • Perimeter = 18.6cm
  • Area = 20.3 cm²

___________________________________________

Answered by Anonymous
21

\;\;\underline{\textbf{\textsf{ Given :-}}}

• Length of rectangle is = 5.8cm

• Breadth is = 3.5 cm

\;\;\underline{\textbf{\textsf{ To Find:-}}}

• Area of the rectangle

• Perimeter of the rectangle

\;\;\underline{\textbf{\textsf{ Solution :-}}}

\underline{\:\textsf{ As we know that :}}

\star\;{\boxed{\sf{\purple{Area_{\;(Rectangle)} = Length × Breadth)}}}}\\ \\

\underline{\:\textsf{ Now,  put the given values :}}

\dashrightarrow \sf Area = 5.8× 3.5\\ \\

\dashrightarrow \sf Area = 20.3\\ \\

\dashrightarrow {\boxed{\frak{\purple{Area= 20.3cm²}}}}\;\\ \\

\;\;\underline{\textbf{\textsf{ Therefore -}}}

\underline{\textsf{Area of the given rectangle  is   \textbf{  20.3cm²}}}.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Again, we are asked to find the perimeter of the given rectangle.

\underline{\:\textsf{We know that :}}

\star\;{\boxed{\sf{\purple{Perimeter_{\;(Rectangle)} = 2(l + b)}}}}\\ \\

\sf Where,

• l = Length

• b = Breadth

\underline{\:\textsf{ Putting  the given values :}}

\dashrightarrow \sf Perimeter  =2(5.8+3.5) \\ \\

\dashrightarrow \sf Perimeter  =18.6cm\\ \\

\dashrightarrow {\boxed{\frak{\purple{Perimeter = 18.6cm }}}}\;\\ \\

\;\;\underline{\textbf{\textsf{ Hence-}}}

\underline{\textsf{Perimeter of the given rectangle  is   \textbf{ 18.6cm }}}.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Similar questions