Q10.The radii of two circles are 19cm and 9cm respectively.Find the radius of a circle of a circle which has circumference equal to sum of their circumferences.
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radius of first circle=19cm
radius of second circle=9cm
radius of third circle be r
circumference of a first circle =2πr=2π[19]=38π
circumference of second circle=2πr=9×2=18π
circumference of third circle=2πr
circumference of 3rd circle=circumference of first circle + circumference of second circle
2πr=38π+18π=56π
r=56π/2π
=28
therefore the radius of the circle which has circumference equal to the sum of the circumference of given two circle is 28
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