Question

Q10. The zeros of polynomial p(x) =
x(x-2)(x+3) are *

0
0,2,3
0,2,-3
None of these​

Answer 1

Answer:

given : p(x) = x(x-2)(x+3)

to find the zeros

Step-by-step explanation:

equate p(x) to zero and solve

=> x(x-2)(x+3) = 0

=> x = 0

=> x-2 = 0 => x = 2

=> (x+3) = 0 => x = -3

therefore zeros are 0, 2 , -3