Question

Q102. In the figure given below two straight lines AB and CD intersect each other at o. If COP = 60°, a, b and c are respectively
А
4c
D
a
3b
2b
C
60°
B
Р
O (A) a=72°, b=270, c=240
O (B) a=60°, b=40°, c=240
O (C) a=72°, b=240, c=270
O (D) a=480, b=169, c=640
(E) a=540,b=240, c=420​

Answer 1

Answer:

InΔCOB&ΔAOD(verticallyoppositeange)

∠COB=∠AOD(alternateinteriorangle)

AB:BC(given)

∴ΔCOB≅ΔAOD(ASAcongurency)

∴OB:OA(CPCT)

andOC=OD(CPCT)

andhenceOisthemidpoint.