Q11. A bag contains 5 black, 8 gold and 7 silver caps. 2. caps are drawn at random and without replacement. What is the probability that both are gold?
O (A) 14/95
O (B) 13/95
O (C) 11/95
O (D) 17/95
Answers
Answered by
0
Answer:
Given 5-white balls
7-red balls
8-black balls
P(no while)
=
20
C
1
15
C
1
×
20
C
1
15
C
1
×
20
C
1
15
C
1
×
20
C
1
15
C
1
=(
20
15
)
4
=(
4
3
)
4
=
256
81
P (at least one white ball ) = 1-P(no white ball)
=1−
250
81
=
256
125
Answered by
1
Answer:
224689974212tu224689974212tu
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