Question

Q11. A man living in a small town with his wife and two children decided to renovate his house of 3 rooms and a hall. He thought of using tiles for flooring of hall only as he couldn’t bear the expenses for using tiles for the rooms. The hall had a dimension of 15 m x 9 m and each square shaped tile has a perimeter of 120cm.


(i) What is the area of one tile in m2 ? (k a) 0.16 m2 b) 0.09 m2 c) 0.016 m2 d) 0.009 m2

(ii). What is the total cost incurred by the man in flooring the hall if cost of each tile is Rs. 20.

(iii). How much extra money does he requires to floor the rest of his house using tiles if each room has a size of 9m x 9m and cost of one tile is Rs.20​

Answer 1

Answer:

i) a. 0.09 m²

ii) Total incurred by the man in flooring the hall is ₹30,000

iii) He requires ₹54,000 extra to floor the rest of his house using tiles.

Step-by-step explanation:

i) Perimeter of the square tile = 120 cm

Therefore, side of the tile = 120/4 cm = 30cm = 0.3m

Area of the tile = (0.3)² m²

=0.09 m²

ii) Area of the hall floor = 15×9 m²

= 135 m²

Now, No of tiles required for flooring = 135/0.09 = 1500.

Total cost of tiles = ₹(1500×20)

= ₹30,000

iii) Area of floor of each room = 9×9 m²

= 81 m²

No. of tiles required to flooring each rooms = 81/0.09

= 900

Cost of tiles for each room = ₹(900×20)

= ₹18,000

Cost of flooring 3 rooms = 3× ₹18,000

= ₹54,000

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Answer 2

Answer: area of each tile is 0.09 m sq and the cost for tiling is rs 30000

Step-by-step explanation:

according to the given data in the question, a man has to renovate his house , in the house he wants the hall to be tiled.

the dimensions of the hall is 15m x 9m. and the each tile measures 120m in perimeter  

the shape of the tile is square.

so as the shape of the tile is square, the perimeter will be given by 4S where S is side of square

$P= 4S$

$P=120=4S\\S=\frac{120}{4}\\S= 30 cm$

Area of a tile =$S^2$

$A= 30*30=900cm^2$

A in meters will be obtained when we will divide the area by 10000

$A(m)=0.09m^2$

now we need to find the cost for flooring

for this we will find the number of tiles on the floor of hall.

$n=\frac{ A(hall)}{A(tile)}$

here n denotes the number of tiles

$n=\frac{1500*900}{900}\\= 1500 tiles$

cost of flooring is the number of tiles multiplied by the cost.

$cost=1500*20\\=rs 30000$

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