Physics, asked by 9416386569shivam28, 8 months ago

Q11: An electric iron draws a current of 3.4 A from the 220 V supply line. What current will
this electric iron draw when connected to 110 V supply line?
Q12: A 6 ohm resistance wire is doubled up by folding. Calculate the new resistance of the wire.​

Answers

Answered by Anonymous
19

Answer 11.

Given that, an electric iron draws a current of 3.4 A from the 220 V supply line.

We have to find the current of the electric iron drawn when connected to 110 V supply line.

From ohm's law we can say that,

V = IR

220 = 3.4 × R

220/3.4 = R

64.7 = R

So, the resistance is 64.7 ohm.

When electric iron is connected to 110 V supply line, then

V = 110V and R = 64.7 ohm

I = V/R

I = 110/64.7

I = 1.7 A

Therefore, the current is 1.7 A when connected to 110 V supply line.

Answer 12.

A 6 ohm resistance wire is doubled up by folding. (R = 6 ohm)

We know that,

R = p l/A = 6

Wire is doubled, means area is doubled and length becomes half the original length.

A = 2A and l = l/2

R' = p (l/2)/2A

R' = p l/4A

R' = 1/4 p l/A

R' = 1/4 × R

As, R = 6 ohm. So,

R' = 6/4

R' = 1.5

Therefore, the new resistance of the wire is 1.5 ohm.

Answered by KakashiHatake7
0

Answer:

Explanation:Given that, an electric iron draws a current of 3.4 A from the 220 V supply line.

We have to find the current of the electric iron drawn when connected to 110 V supply line.

From ohm's law we can say that,

V = IR

220 = 3.4 × R

220/3.4 = R

64.7 = R

So, the resistance is 64.7 ohm.

When electric iron is connected to 110 V supply line, then

V = 110V and R = 64.7 ohm

I = V/R

I = 110/64.7

I = 1.7 A

Therefore, the current is 1.7 A when connected to 110 V supply line.

Answer 12.

A 6 ohm resistance wire is doubled up by folding. (R = 6 ohm)

We know that,

R = p l/A = 6

Wire is doubled, means area is doubled and length becomes half the original length.

A = 2A and l = l/2

R' = p (l/2)/2A

R' = p l/4A

R' = 1/4 p l/A

R' = 1/4 × R

As, R = 6 ohm. So,

R' = 6/4

R' = 1.5

Therefore, the new resistance of the wire is 1.5 ohm.

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