Question

Q11- Consider equation: Pb⁺² (aq) + 2OH⁻ (aq) → Pb(OH)₂ (s). precipitate of lead (II) hydroxide will be of
A) Green color
B) Blue color
C) Brown color
D) White color



Q12- Consider equation: Cu⁺² (aq) + 2OH⁻(aq) → Cu(OH)₂ (s). precipitate of Copper Hydroxide (Cu(OH)₂) will be of
A) Green color
B) Blue color
C) Brown color
D) White color

Answer 1

Answer:

Q11-D)White color

Q12- B)Blue color

Explanation:

Answer 2

The correct option is D.

• The reaction is

Pb⁺² (aq) + 2OH⁻ (aq) → Pb(OH)₂ (s). In this reaction lead cation reacts with hydroxyl ion to form lead hydroxide. The name of the precipitate is lead (II) hydroxide. This is a white colored amorphous solid.

The correct option is B.

• The reaction is-

Cu⁺² (aq) + 2OH⁻(aq) → Cu(OH)₂ (s). In this reaction copper cation reacts with hydroxyl ion to form copper hydroxide. The name of the precipitate is copper (II) hydroxide. This is a bluish green colored solid.