Q11) Find the value of k if (-2, 3) is a solution of x - 2y + k = 0 *
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Answer:
'k' = 8
Step-by-step explanation:
P(f)= x-2y+k
Then (-2,3) is a solution of P(f)
⇒ x= -2, y= 3
We should get zero if we substitute the value of x and y in p(f)
p(f)= (-2) -2(3) +k =0
⇒ -2 -6 +k =0
⇒ -8 +k =0
⇒ k = 8
∴ the value of 'k' is 8
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