Math, asked by kritikabhatnagar0307, 4 months ago

Q11. In an isosceles triangle, the base 2 points
angles are equal. The vertex angle
measures 80°. What is the measure
of the base angles. (use simple
equation)​

Answers

Answered by reenavermahw
3

Answer:

50°

Step-by-step explanation:

Let the measure of the two base angles of isosceles ∆ be x.

One angle = 80°

In a ∆.

Sum of all angles = 180°

80° + x + x = 180°

2x + 20° = 180°

2x = 100°

x = 100° / 2

x = 50°

Hence, the measure of two base angles = 50°

Answered by RanjitKrVerma
1

Answer:

50°

Step-by-step explanation:

Let the measure of the two base angles of isosceles triangle be x.

One angle = 80°

In a triangle,

Sum of all angles = 180°

80° + x + x = 180°

2x + 80° = 180°

2x = 180° - 80°

2x = 100°

x = 100 ° ÷ 2

x = 50°

Hence, the measure of the two base angle = 50°

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