Math, asked by mansababbas70, 1 day ago

Q11. In Fig, angleABC = 69', LACB = 31°, find angleBDC.

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Answered by sachi25

1

Answer:

angle bdc = 90°

coz angle in a semicircle is 90°

also using angle sum property of triangle, BDC= 180-(69+31) =90°

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Answered by chaudharivarsha

0

67 degree angle of BCD in a given figure of questions

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