Question

Q11 In the given figure find the area of the path​

Answer 1

Answer:

Step-by-step explanation:

Area of rectangle ABCD is 110cm x 150cm = 16500cm^2

Area of rectangle EHGF is (110-5-5) x (150-5-5) = 14000cm^2

Area of path is Area ABCD minus Area EHGF = 16500cm^2 -14000cm^2

                                                                            = 2500 cm^2 or 0.25 m^2

Answer 2

Answer:

${16500cm}^{2}$

$15225 {cm}^{2}$

$(16500 - 15225) {cm}^{2}$

$1275 {cm}^{2}$

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