Question

Q12. 01 mole of acetic acid was dissolved in 1 kg of benzene. Depression in
freezing point of benzene was determined to be 0.256 K. What conclusion can you
drow about the state of the solute in solution
12)

Answer 1

∆Tf= iKfm

Where TF is the temperature

i is van hoffs factor

m is molarity

So, putting the values

O.256=i *5.12*0.1

i= 0.5

As, i<1

It Means association is taking place of solute.

So, acetic acid dimerises in solvent.