Question

Q12: 5.5 g CO2 is dissolved in 250 ml of water, molarity of the solution is​

Answer 1

Answer:

Molar mass of Na2CO3 = 46 + 12 + 48 = 106 g/mol

Volume of solution = 250 mL = 0.25L

Molarity = 0.25 M

Molarity, M = Volume of solution in Lmoles of solute,n

 0.25 = 0.25n

n =0.25×0.25 = 0.0625 mol

Mass of 0.0625 mol of sodium carbonate = 0.0625×106 

=6.625g

Explanation:

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Answer 2

Answer:

molar mass of CO2 is 44

no. of moles of CO2 = 5.5 ÷44

molarity = no. of moles × 1000 ÷ vol. in ml

therefore molarity = 5.5 x 1000 ÷ 44 x 250 = 0.5 :)