Question

Q12. A 4-Ohm resistance wire is doubled up by folding. Calculate the new resistance of the
wire. (1)​

Answer 1

Answer:

1Ω

Explanation:

• We consider wire is doubled on it means to fold the length of wire.
• It means its length will get half and area of cross section will get doubled.
• Thus,

R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω