Question

Q12) A 6Ω resistance wire is doubled up by folding. Calculate the new resistance of the

wire.​

Answer 1

Answer:

Given :

R=6ohms

R=ρl/A-------------(1)

Wire is doubled so, Area =A=2A

length=l=l/2

New Reistance will be:

Rnew=ρ(l/2)/2A

Rnew=ρl/4A

Rnew=R/4-----(from equ 1)

Rnew=6/4=1.5 ohms

Hence new Reistance of wire is 1.5ohms.