Question

Q12. A lot of 24 bulbs contains 25% defective bulbs. A bulb is drawn at random from the lot it
is found to be not defective and it is not put back. Now, one bulbis drawn at random from the
rest. What is the probability that this bulb is not defective?​

Answer 1

Answer:

17/23

Step-by-step explanation:

n(s)=24

n(defective bulbs)=25% of 24 which is 6 bulbs.

n(non defective bulbs)=24-6=18

So a non defective bulb is taken out and not defective which means it is from the non defective bulbs.

So now n(non defective bulbs) will be 18-1=17

Now the P(Non defective) = 17/23

Hope this helps..