Q12.A man travelled 8 km 95 m 2 points
in the first hour , 6 km 298 m in
the second hour and 7 km 9 m
in the third hour. How far did
he travel in the three hours.?
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Answer:
A man travelled:
•8km 95 m in the first hour= (8×1000)+95=8095m
•6km 298 m in the second hour=(6×1000)+298=6298m
•7km 9 m in the third hour=(7×1000)+9=7009m
Suming them up, we get the distance:
Total distance:
(8095+6298+7009)m
= 21402 m
hence, he travelled 21402m long in the three hours.
hope it helps :)
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