Hindi, asked by Anonymous, 5 months ago

Q12. A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26cm,28cm,30cm and the parallelogram stands on the base 28cm,find the height of the parallelogram? *



12 cm

14cm

120cm

None

Answers

Answered by balendradubey5bd
32

AnsWer⤵️

Perimeter of Triangle

2S=26+28+30=84

⇒S=42cm

Area

s(s−a)(s−b)(s−c)

(Heron's formula)

Area =

42(42−26)(42−28)(42−30)

=

42×16×14×12

Area=336cm

2

Area of parallelogram = Area of triangle

⇒ h×28=336

⇒h=12cm

Height of parallelogram =12cm

Answered by Anonymous
4

Answer:

Assumption

a = 26 cm

b = 28 cm

c = 30 cm

Hence,

s = 42 cm

Now,

= 2 × 2 × 2 × 2 × 7 cm²

= 16 × 7 cm²

= 336 cm²

Given,

Base × Height = 336 cm²

28cm × Height = 336 cm²

Height = 12 cm

Assumption

a = 26 cm

b = 28 cm

c = 30 cm

Hence,

s = 42 cm

Now,

= 2 × 2 × 2 × 2 × 7 cm²

= 16 × 7 cm²

= 336 cm²

Given,

Base × Height = 336 cm²

28cm × Height = 336 cm²

Height = 12 cm

Explanation:

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