Question

Q12.Find the power dissipated in 6ohm resistance
photo in attachment pls help​

Answer 1

Answer:

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Answer 2

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Given:

A circuit has been provided. The voltage source is 20 V

To find:

Power dissipated in the 6 ohm resistor.

Concept:

First find out the equivalent resistance of the circuit. In that equivalent circuit , find out the current . Then the power dissipated can be easily calculated.

Power is the amount of energy dissipated by the resistance per unit time.

Calculation:

See the diagram for simplified circuit.

The 5 ohm, 4 ohm and 6 ohm are in series.

So net current will be :

$\sf \: I = \dfrac{V}{(5 + 4 + 6)} \\ \\ \sf \implies \: I = \dfrac{20}{(15)} \\ \\ \sf \implies \: I = \dfrac{4}{3} amp.$

Power dissipated in the 6 ohm resistor will be :

$\sf \: P = {(I)}^{2} \times 6 \\ \\ \sf \implies \: P = {( \dfrac{4}{3} )}^{2} \times 6 \\ \\\sf \implies \: P = \dfrac{16}{9} \times 6 \\ \\\sf \implies \: P = 10.66 \: watt$

So final answer :

${ \red{ \sf{ \bold{ P = 10.66 \: watt}}}}$