Q12. If X= 3a +3b +5c; Y = - 7a + 2b – 2c and Z = -a + 7c, find
(i) X + Y + Z
(ii) X – Y
(iii) Y – Z
Answers
Answer:
Given that
x=3a+3b+5c
y=-7a+2b-2c
z=-a+7c
Step-by-step explanation:
(i)
put all value of xyz
= (3a+3b+5c)+(-7a+2b-2c)+(-a+7c)
= 3a -7a -a +3b +2b+5c-2c+7c
= -3a+5b+10c ans
(ii)
put the value of x and z
= (3a+3b+5c)-(-a+7c)
= 3a+3b+5c+a+7c
=3a+a+3b+5c+7c
=4a+3b+12c ans
(iii)
put the value of y and z
=(-7a+2b-2c)-(-a+7c)
=-7a+2b-2c+a+7c
=-7a+a+2b-2c+7c
=-6a+2b-5 ans
Hope it will help you
Step-by-step explanation:
X=3a + 3b + 5c
Y=-7a + 2b - 2c
Z= - a + 7c
i) x + y + z
=) 3a + 3b + 5c + (-7a) + 2b - 2c +
(- a) + 7c
=) 3a - 7a - a +3b +2b +5c - 2c +7c
=) - 5a +5b - 10c
ii) x - y
=) 3a + 3b + 5c - (-7a) + 2b - 2c
=) 3a +3b +5c +7a + 2b - 2c
=)10a + 5b +3c
iii) y-z
=) -7a + 2b - 2c - (- a) + 7c
=) - 7a +2b - 2c +a +7c
=) - 6a +2b +5c