Q12 in electrolysis, if you are passing
current of 30 A for 30 minutes
through a copper sitesi
then identify the mass of sperma
would be deposited
Give Atomic mass of Ou is 6.5
Answers
Answer:
The electrode reaction are: 1 moleCu2 + + 2 × 96500 C2e-→ Cu (Cathode) Cu × Cu2 + + 2e- (Anode) Thus, cathode increases in mass as copper is deposited
Given:
The electric current passed = 30A
The time electric is passed = 30 minutes = 180 seconds
The molar mass of copper = 63.5 g/mol
To Find:
The mass of metal deposited.
Solution:
The copper ion in the solution is reduced to a copper atom.
Cu²⁺ + 2e⁻ → Cu
⇒ 2 Faraday is required to produce 1 mole of copper.
⇒ 2 Faraday = 2 × 96500 Coulombs
Total charge passed through the solution = Q =30 × 180 =5400Coulombs
So, 193000 C charge produces mass = 63.5 g of copper
⇒ 5400 C charge produces mass = (63.5 × 5400) / 193000 g of Cu
⇒ Total mass of copper deposited = 1.78 g
Hence, the total mass of copper deposited is equal to 1.78 grams.