Question

Q12. Solve the following oquations :
(a) 16 = 4 + 3(t + 2)
(b) 4 + 5(p-1) = 34​

Answer 1

Answer:

16 = 4 + 3( t + 2)

$\sf\longrightarrow\sf{ 16 = 4 + 3t + 6}$

$\sf\longrightarrow\sf{ 16 = 10 + 3t}$

$\sf\longrightarrow\sf{ 16 - 10 = 3t}$

$\sf\longrightarrow\sf{ 6 = 3t}$

$\sf\longrightarrow\sf{ t = \dfrac{6}{3}}$

$\sf\longrightarrow\sf{ t = 2}$

4 + 5 ( p - 1 ) = 34

$\sf\longrightarrow\sf{4 + 5 ( p - 1) = 34}$

$\sf\longrightarrow\sf{4 + 5p - 5 = 34}$

$\sf\longrightarrow\sf{5p - 1 = 34}$

$\sf\longrightarrow\sf{5p = 34 + 1}$

$\sf\longrightarrow\sf{5p = 35}$

$\sf\longrightarrow\sf{p = \dfrac{35}{5}}$

$\sf\longrightarrow\sf{p = 7}$