Question

Q12-The compound interest for 2 year on
100 Rs at the rate of 10% per year,
calculated annually? *
O a)11
O b)100
c)21
d)none of these
Other:​

Answer 1

Answer:

21

Step-by-step explanation:

compound interest = 1.1x100(=)²121

subtract 100 from 121 to get interest which is 21 for 2 years

Answer 2

$\frak{Given}\begin{cases}\sf{\;Principal\;(P)=Rs.\frak{\;100}}\\\sf{\;Time\;(n)=\frak{2\;}years}\\\sf{\;Rate\;(R)=\frak{10\;\%}}\end{cases}$

Need to find: Compound interest

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\underline{\bf{\dag}\frak{\;As\;we\;know\;that\;:}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\star\;\boxed{\pink{\sf{C.I=P\bigg\lgroup 1+\dfrac{R}{100}\bigg\rgroup^n-P}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$:\implies\sf{100\bigg\lgroup 1+\dfrac{10}{100}\bigg\rgroup^2-100}\\\\\\\\:\implies\sf{100\bigg\lgroup\dfrac{110}{100}\bigg\rgroup^2-100}\\\\\\\\:\implies\sf{100\times\dfrac{110}{100}\times\dfrac{110}{100}-100}\\\\\\\\:\implies\sf{121-100}\\\\\\\\:\implies\underline{\boxed{\purple{\textsf{\textbf{Rs.\;21}}}}}{\;\bigstar}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\therefore\;{\underline{\sf{Hence,\;the\;compound\;interest\;is\;{\textsf{\textbf{option\;c)\;Rs.\;21}}}}.}}$