Q12 The density of a monoatomic gas becomes 8 times its initial value, in an adiabatic process. If the initial pressure was 0.1 atm, find the final pressure.
•0.8atm
•1.6 atm
•2.4 atm
•3.2 atm
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The answer is as follows:
Explanation:
a0 0.8atm
The adiabatic process is:
- The adiabatic process is one in which no heat is transferred during the process.
- Let's start by looking at how to calculate the work done during adiabatic gas expansion in a closed system.
- ∆U = Q - W.
- For an adiabatic process, Q=0.
- As a result, for a closed system, the work done is determined by the change in the gas's internal energy.
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