Question

Q12) Use suitable identity to factorise each of the follo

ii) x3 - 12x(x - 4) - 64
​

Answer 1

Answer:

(x-4)^3

Step-by-step explanation:

x3 - 12x(x - 4) - 64

= x^3 - 12x^2 + 48x - 64

= x^3 - (3)(x^2)(4) + (3)(x)(4^2) - 4^3

= (x-4)^3

[as (a-b)^3 = a^3 - 3a^2b + 3ab^2 - b^3]