Question

Q13. A body moving with uniform
acceleration in a straight line describes 25 m
in the fifth second and 33 m in the seventh
second. Find its initial velocity and
acceleration.​

Answer 1

Answer:

given,

distance cover in 5sec is 25

distance cover in 7sec is 33

according to 2nd eq of motion,

S= ut+1/2at²

25=u×5+1/2×a×(5)²

25=5u+25a/2

25=10u+25a

2

50= 10u+25a

again,

S=ut+1/2at²

33=u×7+1/2×a×(7)²

33=7u+49a/2

33=14u+49a

2

66=14u+49a

solve the eq by elimination method

.......666......