Question

Q13.A bullet leaves a machine gun at the speed of 100m/s and has a kinetic energy of 1000J. What
is the mass of the bullet?

Answer 1

Answer:

Step-by-step explanation:

The kinetic energy formula  is given as

K = 1/2mv^2

1000 = 1/2m(100)^2

m = 2000/10000 = 2/10

mass = 0.2 kg

Answer 2

Answer:

$\large \implies m=200 \ g$

Step-by-step explanation:

Given :

velocity ( v ) = 100 m / sec

Kinetic energy ( K.E. ) = 1000 J

We have to find mass ( m )

We have formula for K.E.

$\large K.E.=\dfrac{1}{2}mv^2$

Now put the value here we get

$\large 1000.=\dfrac{1}{2}\times m\times(100)^2\\\\\\\large 2000.= m\times10000\\\\\\ \large m=\dfrac{2000}{10000}\\\\\\ \large m=\dfrac{2}{10}\\\\\\ \large m=0.2 \ kg\implies m=200 \ g$

Thus mass of bullet is 200 g.