Question

Q13. A car starts from rest and moves along the X axis with constant acceleration of 5
m/s for 8 seconda, If it then continues with constant velocity, what distance will the
car cover in 12 seconds since it started from rest?​

Answer 1

Answer:

if car moves x dis in 8 sec with accleration 5m/s^2 then

x= ut + at^2 /2

where u =0

so dis covered in 8 sec will be

5×(8^2)×1/2

160

for the next 4 sec final speed will be

v= u+ at

= 40

so dis covered in next 4 sec is vt

= 160

so total dis =160+160=320