Question

Q13. A monkey weighing 50 kg
climbs up a vertical tree of
height 300 m. The potential
energy gained by it g=10m/s *
plzzzz ans fast​

Answer 1

Answer:

mass of boy = m = 50 kg

height = h = 100m

since boy does not move anything with his force, work done by him is zero

work done on the boy = gain in potential energy

P.E=mgh

P.E=50×9.8×100

P.E=49KJ

so, potential energy gained by

Answer 2

Answer:

Given :-

g = 9.8 m/s

height = 300 m

mass = 50 kg

To Find :-

Potential energy gain

Solution :-

We know that

$\sf P_E = mgh$

m = mass = 50 kg

g = acceleration due to gravity = 9.8 m/s

h = height = 0 m

$\sf P_E = 50\times9.8\times0$

$\bf \red{P_E= 0\; J}$

When height = 300 m

$\sf P_E = 50\times 9.8\times300$

$\sf P_E = 147000 J$

Gain = 147000 - 0 = 147000 J