Question

Q13) A solution is prepared from 26.2 x 10-5 kg of an known substance and 112.0 x 10-3 kg acetone
at 313 K. The vapour pressure of pure acetone at this temperature is 0.526 atm. Calculate the vapour
pressure of solution if the molar mass of substance is 273.52 X 10-3 kg mor. (Given the atomic
masses C = 12, H = 1, 0 = 16 )​

Answer 1

Answer:

ANSWER

The molar mass M

2

of non-volatile substance can be calculated from the following formula.

p

0

p

0

−p

=

W

1

×M

2

W

2

×M

1

Here, p

0

vapour pressure of acetone and p is the vapour pressure of the solution.

M

1

and W

1

are the molar mass and mass of acetone.

M

2

and W

2

are the molar mass and mass of a non-volatile substance.

Substitute values in the above expression.

185

185−183

=

100×M

2

1.2×58

Hence, M

2

=64.38g/mol.

Thus, the molar mass of the non-volatile substance is 64 g/mol (approximately).

Answer 2

Answer:

hope it help you

Explanation:

n= n2

-

n1 + n2