Q13. Calculate the wavenumber of the
longest wavelength transition in the Balmer
series of atomic hydrogen?
Answers
Answered by
3
Answer:
i dont no.......sorry frnd
Answered by
2
Answer:
According to Balmer formula
ṽ=1/λ = RH[1/n12-1/n22]
For the Balmer series, ni = 2.
Thus, the expression of wavenumber(ṽ) is given by,
Wave number (ṽ) is inversely proportional to wavelength of transition.
Hence, for the longest wavelength transition, ṽ has to be the smallest.
For ṽ to be minimum, nf should be minimum.
For the Balmer series, a transition from ni = 2 to nf = 3 is allowed.
Hence, taking nf = 3,we get:
ṽ= 1.5236 × 106 m–1
Explanation:
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