Question

Q13. Evaluate the expressions using x = 6, y = 12, z = -3:
(i) 2x+y-z
(ii) y-x

(iv) x²+2y-3z
2 3
(v) 4x² + 4x - 2
Z
+​

Answer 1

pls mark me as a brainliest

Answer 2

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Q1) Evaluate the expression using x=6 ,y=12 and z=-3.

$\underline{\bf\red{Answer-}}$

$\: \bf{(1) \: 2x + y - z}$

$\: \: \underline{ \bf{ \bullet \: put \: the \: given \: values}}$

$\: \implies \displaystyle \sf{2(6) + 12 - ( - 3)}$

$\: \implies \displaystyle \sf{12 + 12 + 3}$

$\: \implies \displaystyle \sf{24 + 3 = 27}$

$\: \bf{(2) \: y - x}$

$\: \implies \displaystyle \sf{12 - 6}$

$\: \implies \displaystyle \sf{6}$

$\: \bf{(3) {x}^{2} + 2y - 3z}$

$\: \implies \displaystyle \sf{ {(6)}^{2} + 2(12) - 3( - 3)}$

$\: \implies \displaystyle \sf{36 + 24 + 9}$

$\: \implies \displaystyle \sf{60 + 9 = 69}$

$\: \bf{(4) {4x}^{2} + 4x - 2}$

$\: \implies \displaystyle \sf{4 {(6)}^{2} + 4(6) - 2}$

$\: \implies \displaystyle \sf{36 \times 4 + 24 - 2}$

$\: \implies \displaystyle \sf{144 + 22}$

$\: \: \implies \displaystyle \sf{166}$

$\: \: \red \bigstar \underline{ \boxed {\bf \color{gray} \: (1)27 \: (2)6 \: (3) 69 \: and \: (4) \: 166 \: are \: the \: solutions}}$