Question

Q13. Find <Q + <R, if QR is diameter of the circle.
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Answer 1

Step-by-step explanation:

⇒ In △PQR,

⇒ PR=QR [ Given ]

∴ ∠RPQ=∠PQR [ Opp angles of equal sides are equal ]

⇒ ∠QRP=90

o

[ Angle inscribed in semi-circle ]

⇒ ∠PQR+∠QRP+∠RPQ=180

o

⇒ ∠RPQ+90

o

+∠RPQ=180

o

∴ 2∠RPQ=180

o

−90

o

∴ 2∠RPQ=90

o

∴ ∠RPQ=45

o