Question

Q13. For what value of k, if x=,√2 is a solution of equation kx2+√2x-4=0​

Answer 1

Answer:

1

Step-by-step explanation:

if x= √2

know kx^2+√2x-4=0

put the value of x

k×{√2×√2} + √2×√2 -4=0

2k +2 -4=0

2k -2=0

2k=2

k=2/2

k=1. ans

hope it helps you.